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Answer by yuri kilochek for Use std::atomic in lambda expression
You can initialize the capture directly and rely on C++17 guaranteed copy/move elision:#include <atomic>int main(){ auto check = [a = std::atomic_int(42)]() mutable { return a.fetch_sub(1) == 1; };}
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I want to capture a std::atomic in a lambda expression. The lifetime of the atomic variable must be tied to the lambda, so I cannot capture by reference, but I want to avoid heap allocation.How can I...
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